WebNote. In the first test case, the hero has to beat a single monster with armor 42, it's enough to have power 43 to achieve that. In the second test case, the hero can pass the level with initial power 13 as follows: enter cave 2: beat a monster with armor 12, power increases to 14; beat a monster with armor 11, power increases to 15; enter cave 1: Webcodeforces 1296D. Fight with Monsters.cpp #include using namespace std; /*** Optimization ***/ #pragma GCC optimize ("Ofast,no-stack-protector") #pragma …

Minimum possible final health of the last monster in a game

Web1786E - Monsters (hard version) - CodeForces Solution. This is the hard version of the problem. In this version, you need to find the answer for every prefix of the monster array. In a computer game, you are fighting against n n monsters. Monster number i i has a i a i health points, all a i a i are integers. A monster is alive while it has at ... WebThe fight with a monster happens in turns. You hit the monster by a a hp. If it is dead after your hit, you gain one point and you both proceed to the next monster. Your opponent … pernicious deed sideboard against

codeforces 1296D. Fight with Monsters.cpp · GitHub

WebIn the third example: A possible order is to fight with the 1 -st, 2 -nd, 3 -rd and 4 -th monsters. After all fights, the health value of the hero becomes − 400. Unfortunately, the … WebContribute to MST9/Codeforces-Solution development by creating an account on GitHub. ... Fight with Monsters.cpp Go to file Go to file T; Go to line L; Copy path Copy … WebCodeForces # 617 (Div. 3) D. Fight with Monsters (greed, sort) There are nn monsters standing in a row numbered from 11 to nn . The ii -th monster has hihi health points (hp). You have your attack power equal to aa hp and your opponent has his attack power equal to bb hp. You and your opponent are fighting these monsters. pernicious definition