WebMay 6, 2024 · In 1979, there were 2.1 million licensed registered nurses in a country This number increased to 3 5 million in 2011 What is the percent increase Consider a circle … WebThe general approach is to write p(k) in terms of the polynomals (k i) with i = 0, 1, 2, … For example, k3 = 6(k 3) + 6(k 2) + (k 1) Now, since n ∑ k = 1(k i) = (n + 1 i + 1) you get: n ∑ k = 1k3 = 6(n + 1 4) + 6(n + 1 3) + (n + 1 2) (There is a slight problem above when i = 0. You really need sums from k = 0 to n for that case.
) Find the value of k if (-2)k+1 × (-2)3 = (-2)7 - Brainly.in
WebMar 28, 2024 · Ex 7.3 , 2 In each of the following find the value of ‘k’, for which the points are collinear. (7, –2), (5, 1), (3, k) Let the given points be A (7, −2), B (5, 1), C (3, k) If the above points are collinear, they will lie on the same line, i.e. the will not form triangle or We can say that Area of ∆ABC = 0 1/2 [x1 (y2 – y3) + x2 (y3 ... WebAug 18, 2024 · 5 ∑ k=2(k +1)2(k − 3) With so few terms, since we're only adding 4, it's easy to just plug in all k values from k = 2 to k = 5 and add them: = (2 +1)2(2 −3) + (3 + 1)2(3 − 3) +(4 +1)2(4 −3) + (5 + 1)2(5 − 3) = 9( −1) +16(0) +25(1) +36(2) = 88. Answer link. dog chat
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WebThe given equation is. (k+1)x 2−2(k−1)x+1=0. comparing it with ax 2+bx+c=0 we get. a=(k+1),b=−2(k−1) and c=1. ∴ Discriminant, D=b 2−4ac=4(k−1) 2−4(k+1)×1. =4(k 2−2k+1)−4k−4. ⇒4k 2−8k+4−4k−4=4k 2−12k. Since roots are real and equal, so. WebEvaluate ∑ k=111 (2+3 k) Medium Solution Verified by Toppr K=1∑11 (2+3 K) = K=1∑11 2+ K=1∑11 3 K =11×2+ (3−1)(3)(3 11−1) =22+ 23(3 11−1) Solve any question of Sequences and Series with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions Let ∑ r=1n r 4=f(n), then ∑ r=1n (2r−1) 4 is equal to Medium View solution > WebAug 28, 2024 · Best answer We know that, if three points are collinear, then the area of triangle formed by these points is zero. Since, the points A (k + 1, 2k), B (3k, 2k + 3) and C (5k - 1, 5k) are collinear. Then, area of ΔABC = 0 1/2 [x1 (y2 – y3) + x2 (y3 - y1 ) + x3 (y1 - y2 )] = 0 Here, x1 = k + 1, x2 = 3k x3 = 5k – 1 And y1 = 2k y2 = 2k + 3 y3 = 5k facts on grocery budget